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An α-particle and a proton are accelerated through same potential difference from rest. Find the ratio of their final velocity
Options
(a) (4:1)
(b) (1:1)
(c) (1:√2)
(d) (1:2)
Correct Answer:
(1:√2)
Explanation:
When a charged particle of charge q and mass m is accelerated from rest through a potential difference V.
.·. Gain in kinetic energy = Loss in potential energy
(1/2) mv² – (1/2) m(0)² = qV or (1/2) mv² = qV or v = √(2qV / m)
For proton, v(p) = √[2eV / m(p)] = √[2eV / m] —–(i)
where m is the mass in atomic mass unit
For α-particle v(α) = √[2(2e)V / m(α)]
= √[2(2e)V / 4m] = (1/√2) v(p)
Therefore, v(α) / v(p) = 1/√2
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e=300 sin[(100 π)t] V
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Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The output of an AND gate is connected to both the inputs of a NOR gate,
- An alternating emf given by equation e=300 sin[(100 π)t] V
- A proton and helium nucleus are shot into a magnetic field at right angles to the field
- In a series resonant LCR circuit, the voltage across R is 100 volts and R =1kΩ
- Two waves represented by following equations are travelling in same medium
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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