| ⇦ | 
| ⇨ |
An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus. The distance of the closest approach is of the order of
Options
(a) 1Å
(b) 10⁻¹⁰ cm
(c) 10⁻¹² cm
(d) 10⁻¹⁵ cm
Correct Answer:
10⁻¹² cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The angle between the dipole moment and electric field at any point on the equatoria
- The flux linked with a coil at any intant t is given by ?=10t² – 50t + 250
- The wing span of an aeroplane is 20 m. It is flying in a field where the vertical
- Ice is wrapped in black and white cloth. In which cases more ice will melt
- A conducting square frame of side ‘a’ and a long straight wire carrying current I
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The angle between the dipole moment and electric field at any point on the equatoria
- The flux linked with a coil at any intant t is given by ?=10t² – 50t + 250
- The wing span of an aeroplane is 20 m. It is flying in a field where the vertical
- Ice is wrapped in black and white cloth. In which cases more ice will melt
- A conducting square frame of side ‘a’ and a long straight wire carrying current I
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply