| ⇦ | 
| ⇨ |
An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus. The distance of the closest approach is of the order of
Options
(a) 1Å
(b) 10⁻¹⁰ cm
(c) 10⁻¹² cm
(d) 10⁻¹⁵ cm
Correct Answer:
10⁻¹² cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A particle moves a distance x in time but according to equation x=(t+5)⁻¹
- The ratio of the acceleration for a solid sphere(mass m and radius R)rolling down
- The phenomenon of radioactivity
- Two resistors of resistances 2Ω and 6Ω are connected in parallel.
- The escape velocity of a body from earth’s surface is Ve. The escape velocity
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle moves a distance x in time but according to equation x=(t+5)⁻¹
- The ratio of the acceleration for a solid sphere(mass m and radius R)rolling down
- The phenomenon of radioactivity
- Two resistors of resistances 2Ω and 6Ω are connected in parallel.
- The escape velocity of a body from earth’s surface is Ve. The escape velocity
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply