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An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus. The distance of the closest approach is of the order of
Options
(a) 1Å
(b) 10⁻¹⁰ cm
(c) 10⁻¹² cm
(d) 10⁻¹⁵ cm
Correct Answer:
10⁻¹² cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Fission of nuclei is possible because the binding energy per nucleon in them
- A certain current on passing through a galvanometer produces a deflection
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Fission of nuclei is possible because the binding energy per nucleon in them
- A certain current on passing through a galvanometer produces a deflection
- An insulated container of gas has two champers seperated by an insulating partition.
- A body oscillates with amplitude of 10 cm in a horizontal platform.
- Wavefront is the locus of all points, where the particles of the medium
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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