| ⇦ | 
| ⇨ |
Amount of calcium oxide required, when it reacts with 852 g of P₄O₁₀ is
Options
(a) 100g
(b) 1008g
(c) 108g
(d) 1050g
Correct Answer:
1008g
Explanation:
6CaO + P₄O₁₀ →2Ca₃(PO₄)₂
6(40+ 16) 4x 31+ 10x 16
=(336) =284
284 g P₄O₁₀ required CaO=336g
852 g P₄O₁₀required CaO=(336x 852)/284=1008 g.
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Question Type: Memory
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Difficulty Level: Easy
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Glycerol on treated with oxalic acid gives
- Bakelite is prepered by the reaction between
- Na₂CO₃ is manufactured by solvay process, the products that are recycled are
- Primary,secondary and tertiary amines can be distinguished by
- Cellulose is polymer of
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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