| ⇦ | 
| ⇨ |
Amount of calcium oxide required, when it reacts with 852 g of P₄O₁₀ is
Options
(a) 100g
(b) 1008g
(c) 108g
(d) 1050g
Correct Answer:
1008g
Explanation:
6CaO + P₄O₁₀ →2Ca₃(PO₄)₂
6(40+ 16) 4x 31+ 10x 16
=(336) =284
284 g P₄O₁₀ required CaO=336g
852 g P₄O₁₀required CaO=(336x 852)/284=1008 g.
Related Questions: - Which of the following is a condensation polymer
- The pair of species with the same bond order is:
- An acyl halide is formed when PCl₅ reacts with an
- Which one of the following compounds exhibit both schottky and frenkel defects
- The number of moles of KMnO₄ that will be needed to react with one mole of
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following is a condensation polymer
- The pair of species with the same bond order is:
- An acyl halide is formed when PCl₅ reacts with an
- Which one of the following compounds exhibit both schottky and frenkel defects
- The number of moles of KMnO₄ that will be needed to react with one mole of
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply