| ⇦ | 
| ⇨ |
Amount of calcium oxide required, when it reacts with 852 g of P₄O₁₀ is
Options
(a) 100g
(b) 1008g
(c) 108g
(d) 1050g
Correct Answer:
1008g
Explanation:
6CaO + P₄O₁₀ →2Ca₃(PO₄)₂
6(40+ 16) 4x 31+ 10x 16
=(336) =284
284 g P₄O₁₀ required CaO=336g
852 g P₄O₁₀required CaO=(336x 852)/284=1008 g.
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Question Type: Memory
(964)
Difficulty Level: Easy
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Topics: Basic Concepts of Chemistry
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Subject: Chemistry
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The pH value of 0.02 M ammonia solution, which is 5% ionised, will be
- Boron has two stable isotopes, ¹°B(19%) and ¹¹B(81%). Average atomic weight
- The given reaction 2FeCl₃ + SnCl₂ → 2FeCl₂ + SnCl₄ is an example of
- Tollen’s test can be used to distinguish
- Due to reference in biological role, Ca²⁺ ions are important in
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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