Amount of calcium oxide required, when it reacts with 852 g of P₄O₁₀ is

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Amount of calcium oxide required, when it reacts with 852 g of P₄O₁₀ is

Options

(a) 100g
(b) 1008g
(c) 108g
(d) 1050g

Correct Answer:

1008g

Explanation:

6CaO + P₄O₁₀ →2Ca₃(PO₄)₂
6(40+ 16) 4x 31+ 10x 16
=(336) =284
284 g P₄O₁₀ required CaO=336g
852 g P₄O₁₀required CaO=(336x 852)/284=1008 g.

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Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)

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