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Amount of calcium oxide required, when it reacts with 852 g of P₄O₁₀ is
Options
(a) 100g
(b) 1008g
(c) 108g
(d) 1050g
Correct Answer:
1008g
Explanation:
6CaO + P₄O₁₀ →2Ca₃(PO₄)₂
6(40+ 16) 4x 31+ 10x 16
=(336) =284
284 g P₄O₁₀ required CaO=336g
852 g P₄O₁₀required CaO=(336x 852)/284=1008 g.
Related Questions: - The most acidic among the following is
- The oxidation states of sulphur in the anions : SO₃²⁻,S₂O₄²⁻ and S₂O₆²⁻
- The hybridization of oxygen atom in H₂O₂ is
- Volume occupied by one molecule of water (density= 1 g cm⁻³) is
- Among the following pairs of ions, the lower oxidation state in aqueous solution
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The most acidic among the following is
- The oxidation states of sulphur in the anions : SO₃²⁻,S₂O₄²⁻ and S₂O₆²⁻
- The hybridization of oxygen atom in H₂O₂ is
- Volume occupied by one molecule of water (density= 1 g cm⁻³) is
- Among the following pairs of ions, the lower oxidation state in aqueous solution
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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