| ⇦ | 
| ⇨ |
Acetylene, on reacting with formaldehyde under high pressure, gives
Options
(a) propanol
(b) propyl alcohol
(c) allyl aldehyde
(d) butyndiol
Correct Answer:
butyndiol
Explanation:
HC ≡ CH + HCHO (Acetylene) → HC ≡ C – CH₂OH (Formaldehyde)
HC ≡ C – CH₂OH + H – C = O → HOCH₂C ≡ CCH₂OH ( But – 2- yn-1,4-diol)
Related Questions: - Neutral divalent carbon species released as reaction intermediate in reaction
- The empirical formula of an acid is CH₂O₂ , the probable molecular formula of
- A compound that undergoes bromination easily is
- Which of the following is correct relationship
- The most efficient agent for the absorption of SO₃ is
Topics: Hydrocarbons
(84)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Neutral divalent carbon species released as reaction intermediate in reaction
- The empirical formula of an acid is CH₂O₂ , the probable molecular formula of
- A compound that undergoes bromination easily is
- Which of the following is correct relationship
- The most efficient agent for the absorption of SO₃ is
Topics: Hydrocarbons (84)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
C2H2+2HCOH=OHCH2CCCH2OH