| ⇦ |
| ⇨ |
Acetylene, on reacting with formaldehyde under high pressure, gives
Options
(a) propanol
(b) propyl alcohol
(c) allyl aldehyde
(d) butyndiol
Correct Answer:
butyndiol
Explanation:
HC ≡ CH + HCHO (Acetylene) → HC ≡ C – CH₂OH (Formaldehyde)
HC ≡ C – CH₂OH + H – C = O → HOCH₂C ≡ CCH₂OH ( But – 2- yn-1,4-diol)
Related Questions: - Sulphur ion is
- If a neutral atoms is converted into a cation, then its
- Element having atomic no.of 56 belongs to which of the following block
- If the initial concentration of the reactant is doubled, the time for half
- The formula for calcium chlorite is
Topics: Hydrocarbons
(84)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Sulphur ion is
- If a neutral atoms is converted into a cation, then its
- Element having atomic no.of 56 belongs to which of the following block
- If the initial concentration of the reactant is doubled, the time for half
- The formula for calcium chlorite is
Topics: Hydrocarbons (84)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

C2H2+2HCOH=OHCH2CCCH2OH