| ⇦ | 
| ⇨ |
Acetylene, on reacting with formaldehyde under high pressure, gives
Options
(a) propanol
(b) propyl alcohol
(c) allyl aldehyde
(d) butyndiol
Correct Answer:
butyndiol
Explanation:
HC ≡ CH + HCHO (Acetylene) → HC ≡ C – CH₂OH (Formaldehyde)
HC ≡ C – CH₂OH + H – C = O → HOCH₂C ≡ CCH₂OH ( But – 2- yn-1,4-diol)
Related Questions: - Which is correct example of condensation polymer
- Alkyl halides can be converted into alcohol in a single step reaction.
- The property,which can be classified as an intensive property, is
- What is the ratio of mass of an electron to the mass of a proton?
- The equilibrium constant for mutarotation α-D Glucose ⇌ β-D Glucose is 1.8.
Topics: Hydrocarbons
(84)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which is correct example of condensation polymer
- Alkyl halides can be converted into alcohol in a single step reaction.
- The property,which can be classified as an intensive property, is
- What is the ratio of mass of an electron to the mass of a proton?
- The equilibrium constant for mutarotation α-D Glucose ⇌ β-D Glucose is 1.8.
Topics: Hydrocarbons (84)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
C2H2+2HCOH=OHCH2CCCH2OH