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Acetylene, on reacting with formaldehyde under high pressure, gives
Options
(a) propanol
(b) propyl alcohol
(c) allyl aldehyde
(d) butyndiol
Correct Answer:
butyndiol
Explanation:
HC ≡ CH + HCHO (Acetylene) → HC ≡ C – CH₂OH (Formaldehyde)
HC ≡ C – CH₂OH + H – C = O → HOCH₂C ≡ CCH₂OH ( But – 2- yn-1,4-diol)
Related Questions: - The base principle of Cottrell’s precipitator is
- What is the approximate percentage of H₂O₂ in a sample labelled as 10 V?
- Which of the following about fluorine is not correct
- When 10 mL of 0.1 M acetic acid (pKa = 5.0 ) is titrated against 10mL of 0.1 M
- Coordination number of Zn in ZnS (zinc blende) is
Topics: Hydrocarbons
(84)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The base principle of Cottrell’s precipitator is
- What is the approximate percentage of H₂O₂ in a sample labelled as 10 V?
- Which of the following about fluorine is not correct
- When 10 mL of 0.1 M acetic acid (pKa = 5.0 ) is titrated against 10mL of 0.1 M
- Coordination number of Zn in ZnS (zinc blende) is
Topics: Hydrocarbons (84)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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C2H2+2HCOH=OHCH2CCCH2OH