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Acetylene, on reacting with formaldehyde under high pressure, gives
Options
(a) propanol
(b) propyl alcohol
(c) allyl aldehyde
(d) butyndiol
Correct Answer:
butyndiol
Explanation:
HC ≡ CH + HCHO (Acetylene) → HC ≡ C – CH₂OH (Formaldehyde)
HC ≡ C – CH₂OH + H – C = O → HOCH₂C ≡ CCH₂OH ( But – 2- yn-1,4-diol)
Related Questions: - Which of the following statement is not correct
- According to Dalton’s atomic theory the smallest partical of the matter is called
- For making distinction between 2-pentanone and 3-pentanone the reagent to be
- A sample of CaCO₃ is 50% pure. On heating 1.12 L of CO₂ at STP is obtained
- 20.0 g of a magnesium carbonate sample decomposes on heating to give carbon dioxide
Topics: Hydrocarbons
(84)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following statement is not correct
- According to Dalton’s atomic theory the smallest partical of the matter is called
- For making distinction between 2-pentanone and 3-pentanone the reagent to be
- A sample of CaCO₃ is 50% pure. On heating 1.12 L of CO₂ at STP is obtained
- 20.0 g of a magnesium carbonate sample decomposes on heating to give carbon dioxide
Topics: Hydrocarbons (84)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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C2H2+2HCOH=OHCH2CCCH2OH