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Acetylene, on reacting with formaldehyde under high pressure, gives
Options
(a) propanol
(b) propyl alcohol
(c) allyl aldehyde
(d) butyndiol
Correct Answer:
butyndiol
Explanation:
HC ≡ CH + HCHO (Acetylene) → HC ≡ C – CH₂OH (Formaldehyde)
HC ≡ C – CH₂OH + H – C = O → HOCH₂C ≡ CCH₂OH ( But – 2- yn-1,4-diol)
Related Questions: - The number of water molecules in gypsum and in plaster of paris are respectively
- 5 mL of N HCl, 20 mL of N/2 H₂SO₄ and 30 mL of N/3 HNO₃ are mixed together
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- How many grams of dibasic acid (mol.wt.200) should be present in 100 mL.
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Topics: Hydrocarbons
(84)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The number of water molecules in gypsum and in plaster of paris are respectively
- 5 mL of N HCl, 20 mL of N/2 H₂SO₄ and 30 mL of N/3 HNO₃ are mixed together
- Which one of the following compounds exhibit both schottky and frenkel defects
- How many grams of dibasic acid (mol.wt.200) should be present in 100 mL.
- At room temperature the eclipsed and staggered forms of ethane can not be isolate
Topics: Hydrocarbons (84)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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C2H2+2HCOH=OHCH2CCCH2OH