| ⇦ | 
| ⇨ |
AB crystallizes in a body centred cubic lattice with edge length ‘a’ equal to 387 pm. The distance between two oppositely charged ions in the lattice is
Options
(a) 335 pm
(b) 250 pm
(c) 200 pm
(d) 300 pm
Correct Answer:
335 pm
Explanation:
For a bcc lattice,
2(r⁺+r⁻) = √3 a
where r⁺ = radius of cation
r⁻ = radius of anion
a = edge length
.·. (r⁺+r⁻) = √3 ⨯ 387/2
= 335.142 pm ≈ 335 pm.
Related Questions: - If principal quantum number n=4, the total number of orbitals having l=3 is
- Alum is a water purifier because it
- An orange dye, p-hydroxyazobenzene can be synthesized from benzene diazonium
- The compounds CHCl₃ and HF lead to the formation of a compound of fluorine
- The predominant intermolecular forces in HF is due to
Topics: Solid State and Solutions
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If principal quantum number n=4, the total number of orbitals having l=3 is
- Alum is a water purifier because it
- An orange dye, p-hydroxyazobenzene can be synthesized from benzene diazonium
- The compounds CHCl₃ and HF lead to the formation of a compound of fluorine
- The predominant intermolecular forces in HF is due to
Topics: Solid State and Solutions (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply