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AB crystallizes in a body centred cubic lattice with edge length ‘a’ equal to 387 pm. The distance between two oppositely charged ions in the lattice is
Options
(a) 335 pm
(b) 250 pm
(c) 200 pm
(d) 300 pm
Correct Answer:
335 pm
Explanation:
For a bcc lattice,
2(r⁺+r⁻) = √3 a
where r⁺ = radius of cation
r⁻ = radius of anion
a = edge length
.·. (r⁺+r⁻) = √3 ⨯ 387/2
= 335.142 pm ≈ 335 pm.
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Topics: Solid State and Solutions
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The range of radius ratio (cationic to anionic) for an octahedral arrangement
- Name of the compound O₂ PtF₆
- DDT is prepared by reacting chlorobenzen with
- The oxide,which can not act as a reducing agent, is
- Haemoglobin is a complex of
Topics: Solid State and Solutions (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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