| ⇦ |
| ⇨ |
A Zenor diode has a contact potential of 1 V in the absence of biasing. It undergoes Zenor breakdown for an electric field of 10⁶ V/m at the depletion region of p-n junction. If the width of the depletion region is 2.5 μm, what should be the reverse biased potential for the Zenor breakdown to occur?
Options
(a) 3.5 V
(b) 2.5 V
(c) 1.5 V
(d) 0.5 V
Correct Answer:
2.5 V
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A wire of length 1 m is moving at a speed of 2 ms⁻¹ perpendicular to its length
- A body takes 5 minute for cooling from 50⁰C to 40⁰C. Its temperature
- The acceleration due to gravity at a place is π² m/sec². Then the time period
- A block of mass 5 kg is moving horizontally at a speed of 1.5 m/s. A perpendicular force
- A particle is kept at rest at the top of a sphere of diameter 42m.When disturbed slightly
Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A wire of length 1 m is moving at a speed of 2 ms⁻¹ perpendicular to its length
- A body takes 5 minute for cooling from 50⁰C to 40⁰C. Its temperature
- The acceleration due to gravity at a place is π² m/sec². Then the time period
- A block of mass 5 kg is moving horizontally at a speed of 1.5 m/s. A perpendicular force
- A particle is kept at rest at the top of a sphere of diameter 42m.When disturbed slightly
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

V=E*d
E=10^6 v/m
d=2.5 μm
Therefor V=2.5