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A wire of resistance 4 ohm is stretched to twice its original length. The resistance of stretched wire would be
Options
(a) 4Ω
(b) 8Ω
(c) 16Ω
(d) 2Ω
Correct Answer:
16Ω
Explanation:
Resistance R = ρℓ / A
ℓ’ = 2 ℓ ⇒ A’ = A / 2
R’ = ρ [2 ℓ / (A / 2)] = 4R = 4 × 4Ω = 16Ω
Related Questions: - An adiabatic process occurs at constant
- We get Balmer series when electron comes from
- If force is proportional to square of velocity, then the dimension of proportionality
- The phase difference between the instantaneous velocity and acceleration of a particle
- Three capacitors each of capacitance C and of breakdown voltage V are joined in series
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An adiabatic process occurs at constant
- We get Balmer series when electron comes from
- If force is proportional to square of velocity, then the dimension of proportionality
- The phase difference between the instantaneous velocity and acceleration of a particle
- Three capacitors each of capacitance C and of breakdown voltage V are joined in series
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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