| ⇦ |
| ⇨ |
A tuning fork of frequency x produces 4 beats with a source of 256 Hz and 8 beats with another source of 268 Hz. Then x equals to
Options
(a) 256 Hz
(b) 260 Hz
(c) 264 Hz
(d) 268 Hz
Correct Answer:
260 Hz
Explanation:
Frequency of tuning fork be x.
.·. x = 256 ± 4 = 260 or 252 Hz.
x = 268 ± 8 = 276 Hz or 260 Hz
.·. x =260 Hz.
Related Questions: - A particle of mass M is suited at the centre of a spherical shell of same mass and radius
- A geostationary satellite is orbiting the earth at a height of 5R above that surface
- A car of mass 1000 kg negotiates a banked curve of radius 90 m on a frictionless
- Electrons of mass m with de-Broglie wavelength λ fall on the target in an X-ray tube.
- A particle moves along the x-axis such that its co-ordinate (x) varies with time (t)
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle of mass M is suited at the centre of a spherical shell of same mass and radius
- A geostationary satellite is orbiting the earth at a height of 5R above that surface
- A car of mass 1000 kg negotiates a banked curve of radius 90 m on a frictionless
- Electrons of mass m with de-Broglie wavelength λ fall on the target in an X-ray tube.
- A particle moves along the x-axis such that its co-ordinate (x) varies with time (t)
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply