⇦ | ![]() | ⇨ |
A tuning fork of frequency x produces 4 beats with a source of 256 Hz and 8 beats with another source of 268 Hz. Then x equals to
Options
(a) 256 Hz
(b) 260 Hz
(c) 264 Hz
(d) 268 Hz
Correct Answer:
260 Hz
Explanation:
Frequency of tuning fork be x.
.·. x = 256 ± 4 = 260 or 252 Hz.
x = 268 ± 8 = 276 Hz or 260 Hz
.·. x =260 Hz.
Related Questions:
- A bomb of mass 30 kg at rest exploded into two pieces of masses 18 kg
- A battery charges a parallel plate capacitor seperated by distance(d) so that the energy
- In Raman effect, Stoke’s lines are spectral lines having
- Two thin dielectric slabs of dielectric constants K₁ and K₂, (K₁ < K₂) are inserted
- Identify the pair whose dimensions are equal
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply