| ⇦ |
| ⇨ |
A tuning fork of frequency x produces 4 beats with a source of 256 Hz and 8 beats with another source of 268 Hz. Then x equals to
Options
(a) 256 Hz
(b) 260 Hz
(c) 264 Hz
(d) 268 Hz
Correct Answer:
260 Hz
Explanation:
Frequency of tuning fork be x.
.·. x = 256 ± 4 = 260 or 252 Hz.
x = 268 ± 8 = 276 Hz or 260 Hz
.·. x =260 Hz.
Related Questions: - A carnot engine working between 300 K and 600 K has a work output of 800J per cycle.
- The term liquid crystal refers to a state that is intermediate between
- When a bullet of mass 10 g and speed 100 ms⁻¹ penetrates up to distance 1 cm
- A beam of light of wavelength 600 nm from a distant source falls
- A radioactive substance emits n beta particles in the first 2 s and 0.5 n beta
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A carnot engine working between 300 K and 600 K has a work output of 800J per cycle.
- The term liquid crystal refers to a state that is intermediate between
- When a bullet of mass 10 g and speed 100 ms⁻¹ penetrates up to distance 1 cm
- A beam of light of wavelength 600 nm from a distant source falls
- A radioactive substance emits n beta particles in the first 2 s and 0.5 n beta
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply