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A transistor is operated in common-emitter configuration at Vᵥ = 2 V such that a change in the base current from 100 µA to 200 µA produces a change in the collector current from 5 mA to 10 mA. The current gain is
Options
(a) 100
(b) 150
(c) 50
(d) 75
Correct Answer:
50
Explanation:
∆Iₑ = ∆Iₘ + ∆Iₙ
β = ∆Iₙ / ∆Iₘ
∆Iₙ = (10 – 5)10⁻³ = 5 x 10⁻³ A
∆Iₘ = (200 – 100)10⁻⁶ = 100 x 10⁻⁶ A
β = 5 x 10⁻³ / 100 x 10⁻⁶ = 5/100 x 1000 = 50
Related Questions: - Dimensions of Torque are
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Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Dimensions of Torque are
- Which scientist experimentally proved the existence of electromagnetic waves?
- Pure Si at 300 k has equal electrons (nₑ) and hole (nh) concentrations
- When radiation is incident on a photoelectron emitter,
- A 36 Ω galvanometer is shunted by resistance of 4 Ω. The percentage of the total current
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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