| ⇦ |
| ⇨ |
A transistor is operated in common-emitter configuration at Vᵥ = 2 V such that a change in the base current from 100 µA to 200 µA produces a change in the collector current from 5 mA to 10 mA. The current gain is
Options
(a) 100
(b) 150
(c) 50
(d) 75
Correct Answer:
50
Explanation:
∆Iₑ = ∆Iₘ + ∆Iₙ
β = ∆Iₙ / ∆Iₘ
∆Iₙ = (10 – 5)10⁻³ = 5 x 10⁻³ A
∆Iₘ = (200 – 100)10⁻⁶ = 100 x 10⁻⁶ A
β = 5 x 10⁻³ / 100 x 10⁻⁶ = 5/100 x 1000 = 50
Related Questions: - An electron moving in a uniform magnetic field of induction of intensity B,
- The masses of two radioactive substances are same and their half lives
- The horizontal range and the maximum height of a projectile are equal
- A potentiometer wire of length 100cm has a resistance of 10Ω. It is connected in series
- Two balls of mass m₁ and m₂ are separated from each other by powder charge
Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An electron moving in a uniform magnetic field of induction of intensity B,
- The masses of two radioactive substances are same and their half lives
- The horizontal range and the maximum height of a projectile are equal
- A potentiometer wire of length 100cm has a resistance of 10Ω. It is connected in series
- Two balls of mass m₁ and m₂ are separated from each other by powder charge
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply