| ⇦ | 
| ⇨ |
A total charge of 5µC is distributed uniformly on the surface of the thin walled semispherical cup. If the electric field strength at the centre of the hemisphere is 9×10⁸NC⁻¹, then the radius of the cup is
{1/4πε₀=9×10⁹N-m²C⁻²}
Options
(a) 5mm
(b) 10mm
(c) 5cm
(d) 10cm
Correct Answer:
5mm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A metal bar of length L and area of cross-section A is clamped between two rigid
- An unpolarised beam of intensity I is incident on a pair of nicols making an angle
- A police jeep is chasing a culprit going on a motorbike.The motorbike crosses
- Two particles A and B, move with constant velocities V₁ and V₂. At the initial
- The decay constant of a radio isotope is λ. If A₁ and A₂ are its activities at time
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A metal bar of length L and area of cross-section A is clamped between two rigid
- An unpolarised beam of intensity I is incident on a pair of nicols making an angle
- A police jeep is chasing a culprit going on a motorbike.The motorbike crosses
- Two particles A and B, move with constant velocities V₁ and V₂. At the initial
- The decay constant of a radio isotope is λ. If A₁ and A₂ are its activities at time
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply