| ⇦ | 
| ⇨ |
A total charge of 5µC is distributed uniformly on the surface of the thin walled semispherical cup. If the electric field strength at the centre of the hemisphere is 9×10⁸NC⁻¹, then the radius of the cup is
{1/4πε₀=9×10⁹N-m²C⁻²}
Options
(a) 5mm
(b) 10mm
(c) 5cm
(d) 10cm
Correct Answer:
5mm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - What is the Q-value of the reaction?
¹H+⁷Li→⁴He+⁴He
- Heat is supplied at constant pressure to diatomic gas. The part of this heat that goes
- A body weighs 50 grams in air and 40 grams in water. How much would it weigh in a liquid
- The voltage gain of an amplifier with 9% negative feedback is 10. The voltage gain
- Calculate the charge on equivalent capacitance of the conbination shown in figure
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- What is the Q-value of the reaction? ¹H+⁷Li→⁴He+⁴He
- Heat is supplied at constant pressure to diatomic gas. The part of this heat that goes
- A body weighs 50 grams in air and 40 grams in water. How much would it weigh in a liquid
- The voltage gain of an amplifier with 9% negative feedback is 10. The voltage gain
- Calculate the charge on equivalent capacitance of the conbination shown in figure
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply