| ⇦ | 
| ⇨ |
A thin ring of radius R meter has charge q coulomb uniformly spread on it. The ring rotates about its axis with a constant frequency of f revolutions/s. The value of magnetic induction in Wb/m² at the centre of the ring is
Options
(a) µ₀q f / 2π R
(b) µ₀q / 2π f R
(c) µ₀q / 2 f R
(d) µ₀q f / 2 R
Correct Answer:
µ₀q f / 2 R
Explanation:
Current in the ring due to the rotation,
I = q/T = q? / 2π = q.2π f / 2π
Therefore, magnetic field at the centre of the ring is
B = µ₀I / 2R = µ₀/2R . q2π f / 2π
= µ₀q f / 2 R
Related Questions: - Two racing cars of masses m₁ and m₂ are moving in circles of radii
- A wire elongates by l mm when a load W is hanged from it. If the wire goes over
- SI unit of magnetic dipole moment is
- A block slides from an inclination of 45°.If it takes time twice
- A uniform rod of length l is placed with one end in contact with the horizontal
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two racing cars of masses m₁ and m₂ are moving in circles of radii
- A wire elongates by l mm when a load W is hanged from it. If the wire goes over
- SI unit of magnetic dipole moment is
- A block slides from an inclination of 45°.If it takes time twice
- A uniform rod of length l is placed with one end in contact with the horizontal
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply