| ⇦ | 
| ⇨ |
A straight conductor 0.1 m long moves in a uniform magnetic field 0.1 T. The velocity of the conductor is 15 ms⁻¹ and is directed perpendicular to the field. The emf indued between the two ends of the conductor is
Options
(a) 0.10 V
(b) 0.15 V
(c) 1.50 V
(d) 15 V
Correct Answer:
0.15 V
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Two slits in Young’s experiment have widths in the ratio 1:25. The ratio of intensity
- Function of a rectifier is
- A tuning fork gives 4 beats with 50 cm length of a sonometer
- The work done in which of the following processes is equal to the change in internal energy
- Initial pressure and volume of a gas are P and 800cc. If the final volume is 100cc
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two slits in Young’s experiment have widths in the ratio 1:25. The ratio of intensity
- Function of a rectifier is
- A tuning fork gives 4 beats with 50 cm length of a sonometer
- The work done in which of the following processes is equal to the change in internal energy
- Initial pressure and volume of a gas are P and 800cc. If the final volume is 100cc
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply