| ⇦ | 
| ⇨ |
A straight conductor 0.1 m long moves in a uniform magnetic field 0.1 T. The velocity of the conductor is 15 ms⁻¹ and is directed perpendicular to the field. The emf indued between the two ends of the conductor is
Options
(a) 0.10 V
(b) 0.15 V
(c) 1.50 V
(d) 15 V
Correct Answer:
0.15 V
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions:
- Length of a string tied to two rigid supports is 40 cm. Maximum length
- A particle doing SHM has amplitude=4 cm and time period = 12 sec. The ratio between times
- A metal wire of circular cross-section has a resistance R₁. The wire is now stretched
- The lowest frequency of light that will cause the emission of photoelectrons
- When a p-n junction is reverse biased, then the current through the junction
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply