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A spherical planet has a mass Mp and diameter Dp. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity, equal to
Options
(a) 4GMp / dp²
(b) GMpm / dp²
(c) GMp / dp²
(d) 4GMpm / dp²
Correct Answer:
4GMp / dp²
Explanation:
Gravitational attraction force on a parcticle B,
Fᵥ = GMₚm / (Dₚ / 2)²
Acceleration of particle due to gravity
a = Fᵥ / m = 4GMₚ / D²ₚ
Related Questions: - A copper disc of radius 0.1 m is rotated about its centre, with 10 revolutions
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A copper disc of radius 0.1 m is rotated about its centre, with 10 revolutions
- Fission of nuclei is possible because the binding energy per nucleon in them
- The radii of circular orbits of two satellites A and B of the earth, are 4R and R
- Which of the following phenomenon exhibited the particle nature of light?
- A black body radiates 20 W at temperature 227⁰C. It temperature of the black body
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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