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A spherical planet has a mass Mp and diameter Dp. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity, equal to
Options
(a) 4GMp / dp²
(b) GMpm / dp²
(c) GMp / dp²
(d) 4GMpm / dp²
Correct Answer:
4GMp / dp²
Explanation:
Gravitational attraction force on a parcticle B,
Fᵥ = GMₚm / (Dₚ / 2)²
Acceleration of particle due to gravity
a = Fᵥ / m = 4GMₚ / D²ₚ
Related Questions: - The weight of a body on surface of earth is 12.6 N. When it is raised to a height
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- Time period of oscillation of a magnet is 2 sec. When it is remagnetised
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The weight of a body on surface of earth is 12.6 N. When it is raised to a height
- A body moves with a uniform acceleration a and zero initial velocity
- Time period of oscillation of a magnet is 2 sec. When it is remagnetised
- A source of light is placed at a distance of 50 cm from a photocell and the stopping
- A circuit area 0.01 m² is kept inside a magnetic field which is normal to its plane.
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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