| ⇦ |
| ⇨ |
A spherical planet has a mass Mp and diameter Dp. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity, equal to
Options
(a) 4GMp / dp²
(b) GMpm / dp²
(c) GMp / dp²
(d) 4GMpm / dp²
Correct Answer:
4GMp / dp²
Explanation:
Gravitational attraction force on a parcticle B,
Fᵥ = GMₚm / (Dₚ / 2)²
Acceleration of particle due to gravity
a = Fᵥ / m = 4GMₚ / D²ₚ
Related Questions: - If particles are moving with same velocity, then maximum de Broglie wavelength will
- A body is thrown vertically upward in air when air resistance is taken into account
- Following figures show the arrangement of bar magnets in different configurations
- In common base mode of a transistor, the collector current is 5.488 mA
- If r be the distance of a point on the axis of a magnetic dipole from its centre
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If particles are moving with same velocity, then maximum de Broglie wavelength will
- A body is thrown vertically upward in air when air resistance is taken into account
- Following figures show the arrangement of bar magnets in different configurations
- In common base mode of a transistor, the collector current is 5.488 mA
- If r be the distance of a point on the axis of a magnetic dipole from its centre
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply