| ⇦ |
| ⇨ |
A source of light is placed at a distance of 50 cm from a photocell and the stopping potential is found to be V₀. If the distance between the light source and photocell is made 25 cm, the new stopping potential will be
Options
(a) 2V₀
(b) V₀ / 2
(c) V₀
(d) 4V₀
Correct Answer:
V₀
Explanation:
Since, stopping potential is independent of distance hence new stopping potential will remain unchanged i.e., new stopping potential = V₀.
Related Questions: - Two identical long conducting wires AOB and COD are placed at right angle
- A body of mass m is placed on the earth’s surface. It is taken from the earth’s surface
- The internal energy change in a system that has absorbed 2 kcals of heat
- Two resistors of 6Ω and 9Ω are connected in series to a 120 V source.
- If the kinetic energy of the particle is increased to 16 times its previous value
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two identical long conducting wires AOB and COD are placed at right angle
- A body of mass m is placed on the earth’s surface. It is taken from the earth’s surface
- The internal energy change in a system that has absorbed 2 kcals of heat
- Two resistors of 6Ω and 9Ω are connected in series to a 120 V source.
- If the kinetic energy of the particle is increased to 16 times its previous value
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply