| ⇦ | 
| ⇨ |
A source and an observer approach each other with same velocity 50 m/s. If the frequency is 435 s⁻¹, then the real frequency is (Velocity of sound=332 m/s)
Options
(a) 320 s⁻¹
(b) 360 s⁻¹
(c) 390 s⁻¹
(d) 420 s⁻¹
Correct Answer:
320 s⁻¹
Explanation:
Both the source and the observer are approaching each other with the same velocity. v = 332 m/s v(o) = v(s) = 50 m/s Therefore, n’ = n.[v + v(o)] / [v – v(s)] 435 = n.[(332 + 50) / (332 – 50)] = (n × 382) / 282 n = (435 × 282) / 382 ≈ 321 ≈ 320 s⁻¹
Related Questions: - A parallel plate air capacitor is charged to a potential difference of V volts.
- A monoatomic gas is suddenly compressed to (1/8)th of its initial volume adiabatically.
- For CE transistor amplifier, the audio signal voltage across the collector resistance
- In common base circuit of a transistor, current amplification factor is 0.95.
- A solid sylinder of mass 3 kg is rolling on a horizontal surface with velocity 4 ms⁻¹
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A parallel plate air capacitor is charged to a potential difference of V volts.
- A monoatomic gas is suddenly compressed to (1/8)th of its initial volume adiabatically.
- For CE transistor amplifier, the audio signal voltage across the collector resistance
- In common base circuit of a transistor, current amplification factor is 0.95.
- A solid sylinder of mass 3 kg is rolling on a horizontal surface with velocity 4 ms⁻¹
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
When source is moving towards stationary object
F’=(v/v-vs)f
When source is stationary and observer is moving
F’=(v+v0/v)f
When both are moving towards each other
F’=(v+v0/v-vs)f
435=(330+50/330-50)f
435=(380/280)f
f=435×280/380
f=435×14/19
f=320.52
f=320s
When source is moving towards stationary object
F’=(v/v-vs)f
When source is stationary and observer is moving
F’=(v+v0/v)f
When both are moving towards each other
f=(v+vo/v-vs)f
435=(330+50/330-50)f
435=(380/280)f
f=435×280/380
f=435×14/19
f=320.52
f=320s