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A simple pendulum performs simple harmonic motion about x = 0 with an amplitude a and time period T. The speed of the pendulum at x = a/2 will be:
Options
(a) πa / T
(b) 3π²a / T
(c) πa√3 / T
(d) πa√3 / 2T
Correct Answer:
πa√3 / T
Explanation:
Speed v = ? √(a² – x²) , x = a / 2
v = ? √(a² – a² / 4) = ? √(3a² / 4) = 2π / T . a√3 / 2
πa√3 / T
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Topics: Oscillations
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If X=3YZ², find dimensions of Y if X and Z are the dimensions of capacity
- An aeroplane is flying horizontally with a velocity of 216 km/h at a height of 1960 m.
- One-fourth length of a spring of force constant K is cut away. The force constant
- Two point charge +9e and +e are at 16 cm away from each other.
- A cockroach is moving with a velocity v in anticlockwise direction on the rim
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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