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A simple pendulum performs simple harmonic motion about x = 0 with an amplitude a and time period T. The speed of the pendulum at x = a/2 will be:
Options
(a) πa / T
(b) 3π²a / T
(c) πa√3 / T
(d) πa√3 / 2T
Correct Answer:
πa√3 / T
Explanation:
Speed v = ? √(a² – x²) , x = a / 2
v = ? √(a² – a² / 4) = ? √(3a² / 4) = 2π / T . a√3 / 2
πa√3 / T
Related Questions: - A train of mass 2x 10⁵ kg has a constant speed of 20 m/s up a hill inclined
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A train of mass 2x 10⁵ kg has a constant speed of 20 m/s up a hill inclined
- A particle doing SHM has amplitude=4 cm and time period = 12 sec. The ratio between times
- If the cold junction of a thermo-couple is kept at 0⁰C and the hot junction is kept
- A common emitter amplifier is designed with n-p-n transistor (α=0.99).
- In a common emitter (CE) amplifier having a voltage gain G, the transistor
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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