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A simple pendulum performs simple harmonic motion about x = 0 with an amplitude a and time period T. The speed of the pendulum at x = a/2 will be:
Options
(a) πa / T
(b) 3π²a / T
(c) πa√3 / T
(d) πa√3 / 2T
Correct Answer:
πa√3 / T
Explanation:
Speed v = ? √(a² – x²) , x = a / 2
v = ? √(a² – a² / 4) = ? √(3a² / 4) = 2π / T . a√3 / 2
πa√3 / T
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body of mass 10 kg is moving on an inclined plane of inclination 30°with an acceleration
- If two charges +4e and +e are at a distance x apart, then at what distance charge q
- A block of mass 0.50 kg is moving with a speed of 2.00 ms⁻¹ on a smooth surface.
- A coil has an area of 0.05 m² and it has 800 turns. It is placed perpendicularly
- The refracting angle of a prism is A and refractive index of the material of the prism
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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