| ⇦ | 
| ⇨ |
A simple pendulum performs simple harmonic motion about x = 0 with an amplitude a and time period T. The speed of the pendulum at x = a/2 will be:
Options
(a) πa / T
(b) 3π²a / T
(c) πa√3 / T
(d) πa√3 / 2T
Correct Answer:
πa√3 / T
Explanation:
Speed v = ? √(a² – x²) , x = a / 2
v = ? √(a² – a² / 4) = ? √(3a² / 4) = 2π / T . a√3 / 2
πa√3 / T
Related Questions: - Two capacitors of capacitances 2 μF and 3 μF are joined in series.
- When 10¹⁹elecrons are removed from a neutral metal plate through some process,
- 1 curie is equal to
- A long wire carrying a steady current is bent into a circular loop of one turn.
- If two vectors are equal in magnitude and their resultant is also equal in magnitude
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two capacitors of capacitances 2 μF and 3 μF are joined in series.
- When 10¹⁹elecrons are removed from a neutral metal plate through some process,
- 1 curie is equal to
- A long wire carrying a steady current is bent into a circular loop of one turn.
- If two vectors are equal in magnitude and their resultant is also equal in magnitude
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply