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A satellite is launched into a circular orbit of radius R around earth while a second satellite is launched into an orbit of radius 1.02R. The percentage difference in the time periods of the two satellites is
Options
(a) 0.7
(b) 1
(c) 1.5
(d) 3
Correct Answer:
3
Explanation:
Apply Kepler’s third law, T²r³=constant
To study the small changes in T and r, take logs and differentiate.
2logT-3logr=log(constant)
2.dT/T-3.dr/r=zero
dT/T=3/2.dr/r
Now change in the radius of the satellite
dR=1.02R-R=0.02R
Percentage change in time period of second satellite with respect to the time period of the first satellite
dT/Tx100%=-3/2 .(0.02R)/Rx100%=3%
Related Questions: - A uniform plank of Young’s modulus Y is moved over a smooth horizontal surface
- The horizontal component of earth’s magnetic field at a place is 3×10⁻⁴ T
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A uniform plank of Young’s modulus Y is moved over a smooth horizontal surface
- The horizontal component of earth’s magnetic field at a place is 3×10⁻⁴ T
- Which of the following pairs of quantities does not have same dimensional
- The velocity of electromagnetic radiation in a medium of permittivity ε₀
- In a ionised gas,the mobile charge carriers are
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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