| ⇦ | 
| ⇨ |
A sample of CaCO₃ is 50% pure. On heating 1.12 L of CO₂ at STP is obtained. Residue left(assuming non volatile impurity) is
Options
(a) 7.8 g
(b) 3.8 g
(c) 2.8 g
(d) 8.9 g
Correct Answer:
7.8 g
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Electronic configuration of deuterium atom is
- Which of the following isomeric alcohols react fastest with HCL
- The compressibility factor of an ideal gas is
- The temperature above which a gas cannot be liquefied is called as
- Boron compounds behave as Lewis acid, because of their
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Electronic configuration of deuterium atom is
- Which of the following isomeric alcohols react fastest with HCL
- The compressibility factor of an ideal gas is
- The temperature above which a gas cannot be liquefied is called as
- Boron compounds behave as Lewis acid, because of their
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply