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A radioactive substance decays to 1/16th of its initial activity in 40 days. The half-life of the radioactive substance expressed in days is
Options
(a) 2.5
(b) 5
(c) 10
(d) 20
Correct Answer:
10
Explanation:
N/N₀ = (1/2)ⁿ
(1/16) = (1/2)ⁿ
n = 4
Half life = t / n = 40 / 4 = 10 day
Related Questions: - The specific charge of a proton is 9.6×10⁷ C/kg. The specific charge of an alpha particle
- Radius of first orbit of the electron in a hydrogen atom is 0.53 Å. So the radius
- Out of the following which pair of quantities does not have same dimensions?
- During negative β-decay
- When a light beam of frequency v is incident on a metal surface,
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The specific charge of a proton is 9.6×10⁷ C/kg. The specific charge of an alpha particle
- Radius of first orbit of the electron in a hydrogen atom is 0.53 Å. So the radius
- Out of the following which pair of quantities does not have same dimensions?
- During negative β-decay
- When a light beam of frequency v is incident on a metal surface,
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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