| ⇦ | 
| ⇨ |
A radioactive substance decays to 1/16th of its initial activity in 40 days. The half-life of the radioactive substance expressed in days is
Options
(a) 2.5
(b) 5
(c) 10
(d) 20
Correct Answer:
10
Explanation:
N/N₀ = (1/2)ⁿ
(1/16) = (1/2)ⁿ
n = 4
Half life = t / n = 40 / 4 = 10 day
Related Questions: - The wave described by y = 0.25 sin (10 2πx – 2πt), where x and y are in meters
- MA⁻¹T⁻² is the dimensional formula of
- An ideal gas is compressed to half its initial volume by means of several processes.
- The radius of curvature of a convave mirror is 24 cm and the imager is magnified
- The drift velocity of free electrons in a conductor is v, when a current
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The wave described by y = 0.25 sin (10 2πx – 2πt), where x and y are in meters
- MA⁻¹T⁻² is the dimensional formula of
- An ideal gas is compressed to half its initial volume by means of several processes.
- The radius of curvature of a convave mirror is 24 cm and the imager is magnified
- The drift velocity of free electrons in a conductor is v, when a current
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply