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A radioactive nucleus of mass M emits a photon of frequency v and the nucleus recoils. The recoil energy will be
Options
(a) Mc² – hv
(b) h²v² / 2Mc²
(c) zero
(d) hv
Correct Answer:
h²v² / 2Mc²
Explanation:
Momentum Mu = E/c = hv / c
Recoil energy
1/2 Mu² = 1/2 . M²u² / M = 1/2M (hv/c)²
= h²v² / 2Mc²
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two capacitors of 10pF and 20pF are connected to 200V and 100V sources, respectively.
- A spherical liquid drop of radius R is divided into 8 equal droplets. If the surface
- An engine has an efficiency of 1/6. When the temperature of sink is reduced
- An ideal heat engine works between temperature T₁=500 K and T₂=375 K.
- When volume of a system is increased two times and temperature is decreased
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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