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A radioactive nucleus of mass M emits a photon of frequency v and the nucleus recoils. The recoil energy will be
Options
(a) Mc² – hv
(b) h²v² / 2Mc²
(c) zero
(d) hv
Correct Answer:
h²v² / 2Mc²
Explanation:
Momentum Mu = E/c = hv / c
Recoil energy
1/2 Mu² = 1/2 . M²u² / M = 1/2M (hv/c)²
= h²v² / 2Mc²
Related Questions: - In a radioactive decay process, the negatively charged emitted β- particles are
- Two spherical conductors A and B of radii 1 mm and 2 mm are separated by a distance
- The near point and far point of a person are 40 cm and 250 cm, respectively.
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a radioactive decay process, the negatively charged emitted β- particles are
- Two spherical conductors A and B of radii 1 mm and 2 mm are separated by a distance
- The near point and far point of a person are 40 cm and 250 cm, respectively.
- An α-particle and a proton travel with the same velocity in a magnetic field
- The temperature at which the vapour pressure of a liquid becomes equal to the external
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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