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A radioactive nucleus of mass M emits a photon of frequency v and the nucleus recoils. The recoil energy will be
Options
(a) Mc² – hv
(b) h²v² / 2Mc²
(c) zero
(d) hv
Correct Answer:
h²v² / 2Mc²
Explanation:
Momentum Mu = E/c = hv / c
Recoil energy
1/2 Mu² = 1/2 . M²u² / M = 1/2M (hv/c)²
= h²v² / 2Mc²
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a double slit experiment, the two slits are 1mm apart and the screen is placed 1 m
- The ionisation potential of hydrogen-atom is -13.6 eV. An electron in the groundstate
- If A=3i+4j and B=7i+24j the vector having the same magnitude as B and parallel to A is
- A single slit Fraunhogger diffraction pattern is formed with white light.
- A long straight wire of radius a carries a steady current I. The current is uniformly
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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