⇦ | ![]() | ⇨ |
A radioactive nucleus of mass M emits a photon of frequency v and the nucleus recoils. The recoil energy will be
Options
(a) Mc² – hv
(b) h²v² / 2Mc²
(c) zero
(d) hv
Correct Answer:
h²v² / 2Mc²
Explanation:
Momentum Mu = E/c = hv / c
Recoil energy
1/2 Mu² = 1/2 . M²u² / M = 1/2M (hv/c)²
= h²v² / 2Mc²
Related Questions:
- Figure below shows two paths that may be taken by a gas to go from a state A
- In a nuclear reactor, the number of U²³⁵ nuclei undergoing fissions per second
- The atomic number of the most common element in nuclear fusion is
- When a radioactive substance emits an ∝ particle, its position in the periodic table
- If the momentum of electron is changed by P, then the de-Broglie wavelength
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply