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A radioactive nucleus of mass M emits a photon of frequency v and the nucleus recoils. The recoil energy will be
Options
(a) Mc² – hv
(b) h²v² / 2Mc²
(c) zero
(d) hv
Correct Answer:
h²v² / 2Mc²
Explanation:
Momentum Mu = E/c = hv / c
Recoil energy
1/2 Mu² = 1/2 . M²u² / M = 1/2M (hv/c)²
= h²v² / 2Mc²
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- For a simple pendulum performing simple harmonic motion, the time period
- A Zenor diode has a contact potential of 1 V in the absence of biasing. It undergoes
- A milli ammeter of range 10 mA has a coil of resistance 1 ohm
- what is the electric potential at a distance of 9cm from 3nC?
- In Young’s double slit experiment, the locus of the point P lying in a plane
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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