| ⇦ |
| ⇨ |
A proton is projected with a speed of 3×10⁶ m/s horizontally from east to west. An uniform magnetic field of strength 2×10⁻³ T exist in the vertically upward direction. What would be the acceleration of proton?
Options
(a) 11.6×10¹¹ m/ s²
(b) 17.4×10¹¹ m/ s
(c) 5.8×10¹¹ m/ s²
(d) 2.9×10¹¹ m/ s²
Correct Answer:
5.8×10¹¹ m/ s²
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Before using the tangent galvanometer, its coil is set in
- Current flows in semi-conductors through
- The magnetic susceptibility does not depend upon the temperature in
- Angular momentum of the particle rotating with a central force is constant due to
- Find the maximum velocity with which a train can be moved on a circular track
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Before using the tangent galvanometer, its coil is set in
- Current flows in semi-conductors through
- The magnetic susceptibility does not depend upon the temperature in
- Angular momentum of the particle rotating with a central force is constant due to
- Find the maximum velocity with which a train can be moved on a circular track
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply