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A person of mass 60 kg is inside a lift of mass 940 kg and presses the button on control panel.The lift starts moving upwards with an acceleration 1.0 m/s². If g = 10 ms⁻², the tension in the supporting cable is
Options
(a) 8600 N
(b) 9680 N
(c) 11000 N
(d) 1200 N
Correct Answer:
11000 N
Explanation:
Total Mass = (60 + 940) kg = 1000 kg
Let T be the tension in the supporting cable, then,
T =M (g+a)
⇒ T = 1000(10+1) =11000 N
Related Questions: - A spring of spring constant 5 x 10³ N/m is stretched initially by 5 cm
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A spring of spring constant 5 x 10³ N/m is stretched initially by 5 cm
- A wire in the form of a circular loop of one turn, carrying a current, produces
- An object is placed 30 cm away from a convex lens of focal length 10 cm and a sharp
- In which of the following heat loss is primarily not due to convection?
- Ice is wrapped in black and white cloth. In which cases more ice will melt
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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