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A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S₁ and that covered in the first 20 seconds is S₂, then:
Options
(a) S₂ = 3S₁
(b) S₂ = 4S₁
(c) S₂ = S₁
(d) S₂ = 2S₁
Correct Answer:
S₂ = 4S₁
Explanation:
u= 0, t₁= 10 s, t₂= 20 s Using the relation, S = ut + 1/2 at²
Acceleration being the same in two cases,
S₁ = 1/2 a x t₁² , S₂ = 1/2 a x t₂²
S₁ / S₂ = ( t₁ / t₂ )² = (10 / 20)² = 1/4
S₂ = 4S₁
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body rolls down a stair case of 5 steps. Each step has height 0.1 m and width 0.1m
- A wire is suspended vertically from one of its ends is stretched by attaching a weight
- A particle is kept at rest at the top of a sphere of diameter 42m.When disturbed slightly
- A particle moving along a straight line OX.At a time (in second ) the distance
- A bimetallic strip consists of metals X and Y. It is mounted rigidly at the base as shown
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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