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A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S₁ and that covered in the first 20 seconds is S₂, then:
Options
(a) S₂ = 3S₁
(b) S₂ = 4S₁
(c) S₂ = S₁
(d) S₂ = 2S₁
Correct Answer:
S₂ = 4S₁
Explanation:
u= 0, t₁= 10 s, t₂= 20 s Using the relation, S = ut + 1/2 at²
Acceleration being the same in two cases,
S₁ = 1/2 a x t₁² , S₂ = 1/2 a x t₂²
S₁ / S₂ = ( t₁ / t₂ )² = (10 / 20)² = 1/4
S₂ = 4S₁
Related Questions: - The ratio of radii of planets A and B is K₁ and ratio of accelerations
- A charged particle (charge q) is moving in a circle of radius R with uniform speed v
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ratio of radii of planets A and B is K₁ and ratio of accelerations
- A charged particle (charge q) is moving in a circle of radius R with uniform speed v
- If A=3i+4j and B=7i+24j the vector having the same magnitude as B and parallel to A is
- In the elastic collision of objects
- The resistance of an ammeter is 13Ω and its scale is graduated for a current
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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