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A particle of masses m is thrown upwards from the surface of the earth, with a velocity u. The mass and the radius of the earth are, respectively, M and R. G is gravitational constant and g is acceleration due to gravity on the surface of the earth. The minimum value of u so that the particle does not return back to earth, is
Options
(a) √( 2GM / R)
(b) √( 2GM / R)²
(c) √( 2G R²)
(d) √( 2GM / R)²
Correct Answer:
√( 2GM / R)
Explanation:
The velocity u should be equal to the escape velocity. That is, u = √(2gR)
But g = GM / R² ⇒ u = √(2 . GM / R² . R)
√( 2GM / R)
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two small spherical shells A and B are given positive charges of 9C and 4C
- A transformer rated at 10 kW is used to connect a 5 kV transmission line to a 240 V
- The maximum kinetic energy of the photoelectrons depends only on
- The mass of a lift is 2000kg. When the tension in the supporting cable is 28000N, then its acceleration is
- A radioactive substance decays to 1/16th of its initial activity in 40 days.
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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