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A particle of masses m is thrown upwards from the surface of the earth, with a velocity u. The mass and the radius of the earth are, respectively, M and R. G is gravitational constant and g is acceleration due to gravity on the surface of the earth. The minimum value of u so that the particle does not return back to earth, is
Options
(a) √( 2GM / R)
(b) √( 2GM / R)²
(c) √( 2G R²)
(d) √( 2GM / R)²
Correct Answer:
√( 2GM / R)
Explanation:
The velocity u should be equal to the escape velocity. That is, u = √(2gR)
But g = GM / R² ⇒ u = √(2 . GM / R² . R)
√( 2GM / R)
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A bullet of mass m moving with velocity v strikes a block of mass M at rests
- One-fourth length of a spring of force constant K is cut away. The force constant
- At what angle should the two forces 2P and √2 P act,so that the resultant force is P√10?
- An ac voltage is applied to a resistance R and an inductor L in series
- In India, electricity is supplied for domestic use at 200V. It is supplied at 110 V
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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