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A particle of masses m is thrown upwards from the surface of the earth, with a velocity u. The mass and the radius of the earth are, respectively, M and R. G is gravitational constant and g is acceleration due to gravity on the surface of the earth. The minimum value of u so that the particle does not return back to earth, is
Options
(a) √( 2GM / R)
(b) √( 2GM / R)²
(c) √( 2G R²)
(d) √( 2GM / R)²
Correct Answer:
√( 2GM / R)
Explanation:
The velocity u should be equal to the escape velocity. That is, u = √(2gR)
But g = GM / R² ⇒ u = √(2 . GM / R² . R)
√( 2GM / R)
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If radius of earth’s orbit is made 1/4, the duration of a year will become
- A car sounding a horn of frequency 100 Hz passes an observer. The ratio
- When photons of energy hν fall on an aluminium plate (of work function E₀),
- An electron of mass m and a photon have same energy E. The ratio of de-Broglie
- A spherical body of emissivity e=0.6, placed inside a perfectly black body is maintained
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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