A particle moving along X-axis has acceleration f,at time t given by f=fₒ(1- t/T)

⇦

⇨

A particle moving along X-axis has acceleration f,at time t given by f=fₒ(1- t/T), where fₒ and T are constants. The particle’s velocity (vₓ) is

Options

(a) fₒT
(b) (1/2)fₒT²
(c) fₒT²
(d) (1/2)fₒT

Correct Answer:

(1/2)fₒT

Explanation:

Acceleration, f = dv/dt = f₀[1-(t/T)]
dv = f₀[1-(t/T)]dt —–(i)
On integrating Equation (i) both sides, we get
.·. v = f₀t – (f₀/T)(t²/2)dt + C —–(ii)
After applying boundery conditions v = 0 at t = 0, we get
Therefore, C = 0
v = f₀t – (f₀/T)(t²/2)dt —–(iii)
As, f = f₀[1-(t/T)]
When, f = 0,t = T
Substituting, t = T in Equation (iii), then velocity
vₓ = f₀T – (f₀/T)(T²/2)
= f₀T – (1/2)f₀T = (1/2)fₒT

Related Questions:

1. A current is flowing through resistance. A potential difference of 120 V
2. The wavelength λₑ of an electron and λₚ of a photon are of same energy E are related by
3. The radius of germanium nuclide is measured to be twice the radius of ₄⁹Be.
4. The distance travelled by a particle starting from rest and moving
5. The fundamental frequency of a closed organ pipe of length 20 cm is equal to the second

Topics: Motion in Straight Line (93)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends