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A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 sec. Then the coefficient of friction is
Options
(a) 0.01
(b) 0.02
(c) 0.03
(d) 0.06
Correct Answer:
0.06
Explanation:
From equation of motion, v = u – at
⇒ o = u – μgt
⇒ μ = u/gt
= 6/(10×10)
= 0.06
Related Questions: - An electron is moving in a circular path under the influence of a transverse magnetic
- In Young’s double slit experiment, the wavelength of the light used is doubled
- Consider the following two statements about Kirchhoff’s law
- A closely wound solenoid of 2000 turns and area of cross-section 1.5 x 10⁻⁴ m² carries
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An electron is moving in a circular path under the influence of a transverse magnetic
- In Young’s double slit experiment, the wavelength of the light used is doubled
- Consider the following two statements about Kirchhoff’s law
- A closely wound solenoid of 2000 turns and area of cross-section 1.5 x 10⁻⁴ m² carries
- The intensity at the maximum in a Young’s double slit experiment is I₀.
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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