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A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 sec. Then the coefficient of friction is
Options
(a) 0.01
(b) 0.02
(c) 0.03
(d) 0.06
Correct Answer:
0.06
Explanation:
From equation of motion, v = u – at
⇒ o = u – μgt
⇒ μ = u/gt
= 6/(10×10)
= 0.06
Related Questions: - A wooden stick 2 m long is floating on the surface of water. The surface tension
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A wooden stick 2 m long is floating on the surface of water. The surface tension
- Out of the following which pair of quantities does not have same dimensions?
- A 100Ω resistance and a capacitor of 100Ω reactance are connected in series
- A battery having e.m.f. 4 volt and internal resistance 0.5 Ω is connected
- During an adiabatic process, the pressure of a gas is found to be proportional
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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