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A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 sec. Then the coefficient of friction is
Options
(a) 0.01
(b) 0.02
(c) 0.03
(d) 0.06
Correct Answer:
0.06
Explanation:
From equation of motion, v = u – at
⇒ o = u – μgt
⇒ μ = u/gt
= 6/(10×10)
= 0.06
Related Questions: - When a biconvex lens of glass having refractive index 1.47 is dipped in a liquid
- A beam of cathode rays is subjected to crossed Electric (E) and Magnetic fields (B)
- Four point masses, each of value m, are placed at the corners of a square ABCD
- The current in the coil of inductance 5H decreases at the rate of 2 A/s
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When a biconvex lens of glass having refractive index 1.47 is dipped in a liquid
- A beam of cathode rays is subjected to crossed Electric (E) and Magnetic fields (B)
- Four point masses, each of value m, are placed at the corners of a square ABCD
- The current in the coil of inductance 5H decreases at the rate of 2 A/s
- A body of mass 3 kg acted upon by a constant force is displaced by S meter
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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