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A particle moves with constant speed v along a circular path of radius r and completes the circle in time T. The acceleration of the particle is
Options
(a) 2πv/T
(b) 2πr/T
(c) 2πr²/T
(d) 2πv²/T
Correct Answer:
2πv/T
Explanation:
Centripetal acceleration = v² / R = v × (v/R) a = v × ω (Therefore, ω = v/R) a = (v × 2π)/T.
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Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A moving coil galvanometer of resistance 100 Ω is converted to ammeter by a resistance
- A 0.01 H inductor and √3 πΩ resistance are connected in series
- If A=4i+4j+4k and b=3i+j+4k, then angle between vectors A and B is
- When one of the slits of Young’s experiment is covered with a transport sheet
- The horizontal range and maximum height of a projectile are equal.The angle of projection
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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