| ⇦ | 
| ⇨ |
A particle moves with constant speed v along a circular path of radius r and completes the circle in time T. The acceleration of the particle is
Options
(a) 2πv/T
(b) 2πr/T
(c) 2πr²/T
(d) 2πv²/T
Correct Answer:
2πv/T
Explanation:
Centripetal acceleration = v² / R = v × (v/R) a = v × ω (Therefore, ω = v/R) a = (v × 2π)/T.
Related Questions: - An ideal spring with spring constant K is hung from the ceiling and a block of mass
- The resistance of a bulb filament is 100 Ω at a temperature of 100⁰C.
- The mean free path of molecules of a gas,(radius ‘r’) is inversely proportional to
- The weight of a body on surface of earth is 12.6 N. When it is raised to a height
- If dimensions of critical velocity of a liquid flowing through a tube are expressed
Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An ideal spring with spring constant K is hung from the ceiling and a block of mass
- The resistance of a bulb filament is 100 Ω at a temperature of 100⁰C.
- The mean free path of molecules of a gas,(radius ‘r’) is inversely proportional to
- The weight of a body on surface of earth is 12.6 N. When it is raised to a height
- If dimensions of critical velocity of a liquid flowing through a tube are expressed
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply