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A particle moves with constant speed v along a circular path of radius r and completes the circle in time T. The acceleration of the particle is
Options
(a) 2πv/T
(b) 2πr/T
(c) 2πr²/T
(d) 2πv²/T
Correct Answer:
2πv/T
Explanation:
Centripetal acceleration = v² / R = v × (v/R) a = v × ω (Therefore, ω = v/R) a = (v × 2π)/T.
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Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In Young’s double slit experiment the distance between the slits and the screen
- A 70 kg man stands in contact against the inner wall of a hollow cylindrical drum
- A sound absorber attenuates the sound level by 20 dB. The intensity decreases
- At what height h above earth, the value of g becomes g/2 (where R=radius of earth)?
- A particle of mass 1.96×10⁻¹⁵ kg is kept in equilibrium between two horizontal metal
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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