A particle moves along with x-axis.The position x of particle with respect to time

⇦

⇨

A particle moves along with x-axis.The position x of particle with respect to time t from origin is given by x=bₒ+b₁t+b₂t².The acceleration of particle is

Options

(a) bₒ
(b) b₁
(c) b₂
(d) 2b₂

Correct Answer:

2b₂

Explanation:

Given, x=b₀+b₁t+b₂t²
Also, v=dx/dt=d/dt(b₀+b₁t+b₂t²)
Using (d/dx).xⁿ=nxⁿ⁻¹, we have
v=b₁+2b₂t
The Acceleration is,
a=dv/dt=d/dt(b₁+2b₂t)
=2b₂

Another Explanation:
Distance , x = b₀ + b₁t + b₂t²
velocity , v = (dx / dt ) = b₁ + 2b₂t
Acceleration, α = d²x / dt² = 2 b₂.

Related Questions:

1. During production of cathode ray
2. The masses of three wires of copper are in the ratio 1:3:5 and lengths
3. As a result of interference of two coherent sources of light, energy is
4. Coherent sources are those sources for which
5. Which of the following substances has the highest elasticity?

Topics: Motion in Straight Line (93)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends