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A particle has initial velocity (2i⃗+3j⃗) and acceleration (0.3i⃗+0.2j⃗). The magnitude of velocity after 10 seconds will be:
Options
(a) 9 √2 units
(b) 5 √2 units
(c) 5 units
(d) 9 units
Correct Answer:
5 √2 units
Explanation:
v⃗ = u⃗ + a⃗t
v = (2i + 3j) + (0.3i + 0.2j) x 10 = 5i +5j
| v⃗ | = √ (5² + 5²)
| v⃗ | = 5 √2
Related Questions: - Two thin dielectric slabs of dielectric constants K₁ and K₂, (K₁ < K₂) are inserted
- In the series resonance the value of impedence is 3 Ω and the resistance is 4Ω,
- If two vectors 2i+3j+k and -4i-6j-λk are parallel to each other, then the value of λ is
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Difficulty Level: Easy
(1008)
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two thin dielectric slabs of dielectric constants K₁ and K₂, (K₁ < K₂) are inserted
- In the series resonance the value of impedence is 3 Ω and the resistance is 4Ω,
- If two vectors 2i+3j+k and -4i-6j-λk are parallel to each other, then the value of λ is
- The kinetic energy of an electron in the first excited state is
- A heavy small sized sphere is suspended by a string of length l.The sphere rotates
Difficulty Level: Easy (1008)
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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