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A particle has initial velocity (2i⃗+3j⃗) and acceleration (0.3i⃗+0.2j⃗). The magnitude of velocity after 10 seconds will be:
Options
(a) 9 √2 units
(b) 5 √2 units
(c) 5 units
(d) 9 units
Correct Answer:
5 √2 units
Explanation:
v⃗ = u⃗ + a⃗t
v = (2i + 3j) + (0.3i + 0.2j) x 10 = 5i +5j
| v⃗ | = √ (5² + 5²)
| v⃗ | = 5 √2
Related Questions: - The charges Q, +q, and +q are placed at the vartices of an equilateral
- A ball is projected upwards from the foot of a tower. The ball crosses the top
- The frequencies of X-rays,γ-rays and ultraviolet rays are respectively p,q and r
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Difficulty Level: Easy
(1008)
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The charges Q, +q, and +q are placed at the vartices of an equilateral
- A ball is projected upwards from the foot of a tower. The ball crosses the top
- The frequencies of X-rays,γ-rays and ultraviolet rays are respectively p,q and r
- The distance of a geo-stationary satellite from the centre of the earth is nearest to
- A body of mass m=3.513 kg is moving along the x-axis with a speed of 5 m/s
Difficulty Level: Easy (1008)
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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