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A particle covers half of its total distance with speed v1 and the rest half distance with speed v2. Its average speed during the complete journey is
Options
(a) (v1v2)/(v1+v2)
(b) (2v1v2)/(v1+v2)
(c) (2v1²v2²)/(v1²+v2²)
(d) (v1+v2)/2
Correct Answer:
(2v1v2)/(v1+v2)
Explanation:
Let the tot. distance covered by the particles be 2s. Then
vₐᵥ = 2 s / (s/ v₁ + s/ v₂) = 2 v₁v₂ / v₁ + v₂
Related Questions: - The nuclei of which one of the following pairs of nuclei are isotones?
- Wb/m² is equal to
- If |A x B|= √3 A.B , then the value of |A + B| is
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The nuclei of which one of the following pairs of nuclei are isotones?
- Wb/m² is equal to
- If |A x B|= √3 A.B , then the value of |A + B| is
- A Galilean telescope has an objective of focal length 100 cm and magnifying power 50
- Two coils have the mutual inductance of 0.05 H.
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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