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A parallel beam of light of wavelength λ is incident normally on a narrow slit. A diffraction pattern is formed on a screen placed perpendicular to the direction of the incident beam. At the second minimum of the diffraction pattern, the phase difference between the rays coming from the two edges of slit is
Options
(a) πλ
(b) 2π
(c) 3π
(d) 4π
Correct Answer:
4π
Explanation:
Condition for the diffraction minima are
Path diff. ∆x = nλ and Phase diff. ?ﾝﾜﾙ = 2nπ
Path diff. = nλ = 2λ
Phase diff. = 2nπ = 4π (n=2)
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Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The thermo e.m.f. E in volts of a certain thermocouple is found to vary
- The electric potential V at any point (x,y,z) all in meters in space is given by
- An object is placed at a distance of 10 cm from a co-axial combination of two lenses
- If a nucleus ᴢXᴬ emits 9α and 5β-particles, then the ratio of total protons and neutrons
- In R-L-C series circuit, the potential differences across each element is 20 V.
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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