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A parallel beam of light of wavelength λ is incident normally on a narrow slit. A diffraction pattern is formed on a screen placed perpendicular to the direction of the incident beam. At the second minimum of the diffraction pattern, the phase difference between the rays coming from the two edges of slit is
Options
(a) πλ
(b) 2π
(c) 3π
(d) 4π
Correct Answer:
4π
Explanation:
Condition for the diffraction minima are
Path diff. ∆x = nλ and Phase diff. ?ﾝﾜﾙ = 2nπ
Path diff. = nλ = 2λ
Phase diff. = 2nπ = 4π (n=2)
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Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ionisation potential of hydrogen-atom is -13.6 eV. An electron in the groundstate
- In Young’s double slit interference experiment, using two coherent waves
- The capacitance of two concentric spherical shells of radii R₁ and R₂ (R₂>R₁) is
- Zenor breakdown will occur if
- An electron of mass Mₑ, initially at rest, moves through a certain distance in a uniform
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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