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A parallel beam of light of wavelength λ is incident normally on a narrow slit. A diffraction pattern is formed on a screen placed perpendicular to the direction of the incident beam. At the second minimum of the diffraction pattern, the phase difference between the rays coming from the two edges of slit is
Options
(a) πλ
(b) 2π
(c) 3π
(d) 4π
Correct Answer:
4π
Explanation:
Condition for the diffraction minima are
Path diff. ∆x = nλ and Phase diff. ?ﾝﾜﾙ = 2nπ
Path diff. = nλ = 2λ
Phase diff. = 2nπ = 4π (n=2)
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Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An electron in potentiometer experiences a force 2.4×10⁻¹⁹N. The length of potentiometer
- Find out the e.m.f. produced when the current changes from 0 to 1 A in 10 sec.
- Two identical capacitors each of capacitance 5 mF are charged potentials 2 kV and 1 kV
- The wavelength of Kα line in copper is 1.5Å. The ionisation energy of K electron in copper is
- The intensity at the maximum in a Young’s double slit experiment is I₀.
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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