| ⇦ |
| ⇨ |
A parallel beam of light of wavelength λ is incident normally on a narrow slit. A diffraction pattern is formed on a screen placed perpendicular to the direction of the incident beam. At the second minimum of the diffraction pattern, the phase difference between the rays coming from the two edges of slit is
Options
(a) πλ
(b) 2π
(c) 3π
(d) 4π
Correct Answer:
4π
Explanation:
Condition for the diffraction minima are
Path diff. ∆x = nλ and Phase diff. ?ンワル = 2nπ
Path diff. = nλ = 2λ
Phase diff. = 2nπ = 4π (n=2)
Related Questions: - A force F=ai+3j+6k is acting at a point r=2i-6j-12k. The value of α for
- If capillary experiment is performed in vaccum, then a liquid under the condition
- If angular momentum of a body is increased by 200% its kinetic energy will increase
- You are marooned on a frictionless horizontal plane and cannot exert any horizontal
- A geostationary satellite is orbiting the earth at a height of 5R above that surface
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A force F=ai+3j+6k is acting at a point r=2i-6j-12k. The value of α for
- If capillary experiment is performed in vaccum, then a liquid under the condition
- If angular momentum of a body is increased by 200% its kinetic energy will increase
- You are marooned on a frictionless horizontal plane and cannot exert any horizontal
- A geostationary satellite is orbiting the earth at a height of 5R above that surface
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply