| ⇦ | 
| ⇨ |
A nucleus ᵐₙ X emits one α- particle and two β- particles. The resulting nucleus is
Options
(a) ᵐ⁻⁶ₙ₋₄ Z
(b) ᵐ⁻⁶ₙ Z
(c) ᵐ⁻⁴ₙ X
(d) ᵐ⁻⁴ₙ₋₂ Y
Correct Answer:
ᵐ⁻⁴ₙ X
Explanation:
When ᵐₙ X emits one α- particle then its atomic mass decreases by 4 units and atomic number4 by 2. Therefore, the new nucleus becomes ᵐ⁻⁴ₙ₋₂ Y. But as it emits two β⁻ particles, its atomic number incre4ases by 2. Thus the resulting nucleus is ᵐ⁻⁴ₙ X.
Related Questions: - The potential energy of a 1 kg particle free to move along the x-axis is given by
- Two lines of force due to a bar magnet
- A particle of mass 1mg has the same wavelength as an electron moving with a velocity
- In an electrical circuit R,L,C and an AC voltage source are all connected in series.
- The escape velocity from the earth is Ve. The escape velocity from a planet
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The potential energy of a 1 kg particle free to move along the x-axis is given by
- Two lines of force due to a bar magnet
- A particle of mass 1mg has the same wavelength as an electron moving with a velocity
- In an electrical circuit R,L,C and an AC voltage source are all connected in series.
- The escape velocity from the earth is Ve. The escape velocity from a planet
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply