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A nucleus ᵐₙ X emits one α- particle and two β- particles. The resulting nucleus is
Options
(a) ᵐ⁻⁶ₙ₋₄ Z
(b) ᵐ⁻⁶ₙ Z
(c) ᵐ⁻⁴ₙ X
(d) ᵐ⁻⁴ₙ₋₂ Y
Correct Answer:
ᵐ⁻⁴ₙ X
Explanation:
When ᵐₙ X emits one α- particle then its atomic mass decreases by 4 units and atomic number4 by 2. Therefore, the new nucleus becomes ᵐ⁻⁴ₙ₋₂ Y. But as it emits two β⁻ particles, its atomic number incre4ases by 2. Thus the resulting nucleus is ᵐ⁻⁴ₙ X.
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- One-fourth length of a spring of force constant K is cut away. The force constant
- If force(F),velocity(v) and time(T) are taken as units, then the dimensions of mass are
- ₉₂U²³⁴ has 92 protons and 238 nucleons. It decays by emitting an alpha particle
- The transition from the state 3 n = 3 to n = 1 in a hydrogen like atom results
- The nuclear fusion reaction between deutrium and tritium takes place
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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