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A nucleus ᵐₙ X emits one α- particle and two β- particles. The resulting nucleus is
Options
(a) ᵐ⁻⁶ₙ₋₄ Z
(b) ᵐ⁻⁶ₙ Z
(c) ᵐ⁻⁴ₙ X
(d) ᵐ⁻⁴ₙ₋₂ Y
Correct Answer:
ᵐ⁻⁴ₙ X
Explanation:
When ᵐₙ X emits one α- particle then its atomic mass decreases by 4 units and atomic number4 by 2. Therefore, the new nucleus becomes ᵐ⁻⁴ₙ₋₂ Y. But as it emits two β⁻ particles, its atomic number incre4ases by 2. Thus the resulting nucleus is ᵐ⁻⁴ₙ X.
Related Questions: - When an α-particle of mass m moving with velocity ν bombards on a heavy nucleus
- If particles are moving with same velocity, then maximum de Broglie wavelength will
- A light of wavelength 5000Å falls on a sensitive plate with photoelectric work
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When an α-particle of mass m moving with velocity ν bombards on a heavy nucleus
- If particles are moving with same velocity, then maximum de Broglie wavelength will
- A light of wavelength 5000Å falls on a sensitive plate with photoelectric work
- When a sound wave of wavelength λ is propagating in a medium,
- The number of possible natural oscilations of air column in a pipe closed
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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