| ⇦ | 
| ⇨ |
A nucleus ᵐₙ X emits one α- particle and two β- particles. The resulting nucleus is
Options
(a) ᵐ⁻⁶ₙ₋₄ Z
(b) ᵐ⁻⁶ₙ Z
(c) ᵐ⁻⁴ₙ X
(d) ᵐ⁻⁴ₙ₋₂ Y
Correct Answer:
ᵐ⁻⁴ₙ X
Explanation:
When ᵐₙ X emits one α- particle then its atomic mass decreases by 4 units and atomic number4 by 2. Therefore, the new nucleus becomes ᵐ⁻⁴ₙ₋₂ Y. But as it emits two β⁻ particles, its atomic number incre4ases by 2. Thus the resulting nucleus is ᵐ⁻⁴ₙ X.
Related Questions: - The displacement ‘x’ (in meter) of a particle of mass ‘m’ (in kg) moving in one
- What is the dimension of impedance?
- Two parallel beams of positron moving in the same direction will
- If the band gap between valence band and conduction band in a material is 5.0 eV,
- 1 curie is equal to
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The displacement ‘x’ (in meter) of a particle of mass ‘m’ (in kg) moving in one
- What is the dimension of impedance?
- Two parallel beams of positron moving in the same direction will
- If the band gap between valence band and conduction band in a material is 5.0 eV,
- 1 curie is equal to
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply