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A nucleus ᵐₙ X emits one α- particle and two β- particles. The resulting nucleus is
Options
(a) ᵐ⁻⁶ₙ₋₄ Z
(b) ᵐ⁻⁶ₙ Z
(c) ᵐ⁻⁴ₙ X
(d) ᵐ⁻⁴ₙ₋₂ Y
Correct Answer:
ᵐ⁻⁴ₙ X
Explanation:
When ᵐₙ X emits one α- particle then its atomic mass decreases by 4 units and atomic number4 by 2. Therefore, the new nucleus becomes ᵐ⁻⁴ₙ₋₂ Y. But as it emits two β⁻ particles, its atomic number incre4ases by 2. Thus the resulting nucleus is ᵐ⁻⁴ₙ X.
Related Questions: - The nuclear radius of a certain nucleus is 7.2 fm and it has a charge of 1.28×10⁻¹⁷ C.
- The self-inductance of a choke coil is 10 mH. When it is connected with a 10 V DC source,
- A neutron is moving with a velocity u.It collides head on and elastically with an atom
- Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The nuclear radius of a certain nucleus is 7.2 fm and it has a charge of 1.28×10⁻¹⁷ C.
- The self-inductance of a choke coil is 10 mH. When it is connected with a 10 V DC source,
- A neutron is moving with a velocity u.It collides head on and elastically with an atom
- Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å
- A plank with a box on it at one end is gradually raised about the other end.
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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