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A ballet dancer, dancing on smooth floor, is spinning about a vertical axis with her arms folded with an angular velocity of 20 radian/sec. When she stretches her arms fully, the spinning speed decreases to 10 radian/sec. If l is the initial moment of inertia of the dancer, the new moment of inertia is
Options
(a) 2I
(b) 3I
(c) I/2
(d) I/3
Correct Answer:
2I
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A short linear object of length L lies on the axis of a spherical mirror of focal
- If F⃗ is the force acting on a particle having position vector r⃗ and ? ⃗ be the torque
- If the length of a stretched string is shortened by 4% and the tension is increased
- A road of width 20 m forms an arc of radius 15 m,its outer edge is 2m higher than
- The weight of a body on surface of earth is 12.6 N. When it is raised to a height
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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Since MI is inversely proportional to angular velocity. then if angular velocity=20 rad/sec. Gets half to 10 rad /sec .therfore moment of inertia will get doubled. Therefore correct anwers is 2l