| ⇦ | 
| ⇨ |
A nucleus ᴢXᴬ emits an α- particle with velocity v. The recoil speed of the daughter nucleus is
Options
(a) A-4/4v
(b) 4v/A-4
(c) v
(d) v/4
Correct Answer:
4v/A-4
Explanation:
According to the question, zXᴬ → z-₂ Yᴬ⁻⁴ + ₂He⁴
Let the recoil speed of daughter nucleus is ʋ’. By the law of conservation of momentum, we have Initial momentum = Final momentum
0 = (A – 4)ʋ’ + 4ʋ
(A – 4) ʋ’ = -4ʋ ⇒ ʋ’ = 4ʋ / (A – 4)
Related Questions: - A solid which is transparent to visible light and whose conductivity increases
- Rate of photoelectric emission is proportional to
- An isolated sphere has a capacitance of 50pF. What would be the radius of the sphere?
- A cell can be balanced against 110 cm and 100 cm of potentiometer wire, respectively
- Ring, hollow ring and solid sphere are rolled down from inclined plane
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A solid which is transparent to visible light and whose conductivity increases
- Rate of photoelectric emission is proportional to
- An isolated sphere has a capacitance of 50pF. What would be the radius of the sphere?
- A cell can be balanced against 110 cm and 100 cm of potentiometer wire, respectively
- Ring, hollow ring and solid sphere are rolled down from inclined plane
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply