| ⇦ | 
| ⇨ |
A nucleus ᴢXᴬ emits an α- particle with velocity v. The recoil speed of the daughter nucleus is
Options
(a) A-4/4v
(b) 4v/A-4
(c) v
(d) v/4
Correct Answer:
4v/A-4
Explanation:
According to the question, zXᴬ → z-₂ Yᴬ⁻⁴ + ₂He⁴
Let the recoil speed of daughter nucleus is ʋ’. By the law of conservation of momentum, we have Initial momentum = Final momentum
0 = (A – 4)ʋ’ + 4ʋ
(A – 4) ʋ’ = -4ʋ ⇒ ʋ’ = 4ʋ / (A – 4)
Related Questions: - The maximum particle velocity in a wave motion is half the wave velocity.
- A microscope is having objective of focal length 1 cm and eye-piece of focal length 6 cm.
- Two lines of force due to a bar magnet
- A body oscillates with amplitude of 10 cm in a horizontal platform.
- Two waves are represented by the equations y₁ = a sin (?t + kx + 0.57) m
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The maximum particle velocity in a wave motion is half the wave velocity.
- A microscope is having objective of focal length 1 cm and eye-piece of focal length 6 cm.
- Two lines of force due to a bar magnet
- A body oscillates with amplitude of 10 cm in a horizontal platform.
- Two waves are represented by the equations y₁ = a sin (?t + kx + 0.57) m
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply