A nucleus ᴢXᴬ emits an α- particle with velocity v. The recoil speed of the daughter

⇦

⇨

A nucleus ᴢXᴬ emits an α- particle with velocity v. The recoil speed of the daughter nucleus is

Options

(a) A-4/4v
(b) 4v/A-4
(c) v
(d) v/4

Correct Answer:

4v/A-4

Explanation:

According to the question, zXᴬ → z-₂ Yᴬ⁻⁴ + ₂He⁴

Let the recoil speed of daughter nucleus is ʋ’. By the law of conservation of momentum, we have Initial momentum = Final momentum

0 = (A – 4)ʋ’ + 4ʋ

(A – 4) ʋ’ = -4ʋ ⇒ ʋ’ = 4ʋ / (A – 4)

Related Questions:

1. Two satellites of earth, S₁ and S₂ are moving in the same orbit. The mass of S₁
2. Dimensions of resistance in an electrical circuit, in terms of dimension of mass M,
3. Dependence of intensity of gravitational field (E) of earth with distance(r)
4. Aperture of human eye is 0.2 cm. The minimum magnifying power of a visual
5. Maximum velocity of the photoelectron emitted by a metal is 1.8×10⁶ ms⁻¹.

Topics: Radioactivity (83)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends