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A nucleus disintegrates into two nuclear parts which have their velocities in the ratio 2 : 1. The ratio of their nuclear sizes will be
Options
(a) 2¹/³ : 1
(b) 1 : 3¹/²
(c) 3¹/² : 1
(d) 1 : 2¹/³
Correct Answer:
1 : 2¹/³
Explanation:
Law of conservation of momentum gives m₁v₁ = m₂v₂
Therefore, m₁/m₂ = v₁/v₂ = 1/2
We know that, R = R₀.A¹/³
Where R is radius of nucleus and A is mass number.
.·. (R₁/R₂) = [A₁/A₂]¹/³ = [m₁/m₂]¹/³ = (1/2)¹/³
⇒ (R₁/R₂) = 1 / (2¹/³)
⇒ R₁ : R₂ = 1 : 2¹/³
Related Questions: - A body oscillates with amplitude of 10 cm in a horizontal platform.
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body oscillates with amplitude of 10 cm in a horizontal platform.
- A thin ring of radius R meter has charge q coulomb uniformly spread on it
- An objective moves ,starting from rest through a resistive medium
- A thermally insulated rigid container contains an ideal gas heated by a filament
- The velocity of molecules of a gas at temperature 120 K is v. At what temperature
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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